Alarm. - This is an electronic circuit schematic of Motor Burn Out and Under Voltage Protection using CA3130 IC like in Figure 1 below. In this circuit schematic the basic component used is CA3130 IC.
In here we will give you global description about circuit schematic of Motor Burn Out and Under Voltage Protection using CA3130 IC and then we will give you link to continue your reading from original source as external website.
In here we will give you global description about circuit schematic of Motor Burn Out and Under Voltage Protection using CA3130 IC and then we will give you link to continue your reading from original source as external website.
Circuit Schematic
Component Part
- R1, R3, R8_______1K
- R2______________1.2K
- R4______________10K
- R5______________47K
- R6, R7___________4.7K
- VR1- potentiometer__4.7K
- C1__Electrolytic_____470uF/25V
- C2__Ceramic__________10uF/16V
- C3__Electrolytic_____100uF/16V
- C4__Ceramic_________150pF/50V
- D1-D5___1N4001__1A 50V Diode
- ZD1_____3.6V/0.5W Zener
- Q1, Q2_____BC548___0.4A 40V NPN transistors
- IC1________CA3130___
- RY1___Relay _____ 12V__1C
- T1___Transformer__12V/0.5A
- Box, PCB, Wires with plug 220V, etc.
Description
Circuit schematic like in Figure 1 above is Circuit Schematic Motor Burn Out and Under Voltage Protection using CA3130 IC. Eleccircuit site describe that this is AC motor burn out protection causes of under voltage input. The principle is simple, it will check for voltage at all times. Normal voltage is 220V AC. If the voltage falls below a preset. Relay will not work and the LED is a warning. Can be set to cut no-off in the voltage during the 168-227V.
As AC main in normal level, the relay will be connect to apply AC line to motor. And AC-line fall down lower than 10% of normal voltage the relay will cut of load at once. Until the voltage is restored to its original condition. So to get back into the circuit again.
As AC main in normal level, the relay will be connect to apply AC line to motor. And AC-line fall down lower than 10% of normal voltage the relay will cut of load at once. Until the voltage is restored to its original condition. So to get back into the circuit again.
And now you can read more you knowledge about Circuit Schematic of Motor Burn Out and Under Voltage Protection using CA3130 IC from the original source article using link [here].
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